(3x^2+4x+1)(x+1)=0

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Solution for (3x^2+4x+1)(x+1)=0 equation: 


Simplifying
(3x2 + 4x + 1)(x + 1) = 0

Reorder the terms:
(1 + 4x + 3x2)(x + 1) = 0

Reorder the terms:
(1 + 4x + 3x2)(1 + x) = 0

Multiply (1 + 4x + 3x2) * (1 + x)
(1(1 + x) + 4x * (1 + x) + 3x2 * (1 + x)) = 0
((1 * 1 + x * 1) + 4x * (1 + x) + 3x2 * (1 + x)) = 0
((1 + 1x) + 4x * (1 + x) + 3x2 * (1 + x)) = 0
(1 + 1x + (1 * 4x + x * 4x) + 3x2 * (1 + x)) = 0
(1 + 1x + (4x + 4x2) + 3x2 * (1 + x)) = 0
(1 + 1x + 4x + 4x2 + (1 * 3x2 + x * 3x2)) = 0
(1 + 1x + 4x + 4x2 + (3x2 + 3x3)) = 0

Combine like terms: 1x + 4x = 5x
(1 + 5x + 4x2 + 3x2 + 3x3) = 0

Combine like terms: 4x2 + 3x2 = 7x2
(1 + 5x + 7x2 + 3x3) = 0

Solving
1 + 5x + 7x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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